U=10 V, R=10 ohm
I calculated the resistance as such:
1/Rt = 1/R + 1/R <=> Rt = R/2 = 5 ohm
To calculate the voltage I did KVL as such:
U – 2Ur = 0 <=> Ur = 5V, where Ur is the voltage in the resistors
And then by applying KVL to the closed network that goes from a to b passing through the resistor, I got Ut=5V
Then I calculated the current using U=RI, and I got I=1A.
Is this correct? Because in my solutions I=0,5A
Best Answer
I answered your last question here.
Once again, you have the right answer and your "solution" answer is wrong.
You have done the correct method; found the open-circuit terminal voltage, which is the Thevenin voltage. You have then found the Thevenin resistance - also correct. You have then used the transform \$ I_n = V_{th}/R_{th}\$ to find the Norton current, correct again.
Good job - wherever you keep getting your solution answers from, stop using it!!!