circuit analysisdiodeskvl
To understand modern semiconductor diodes, I looked up their simpler predecessors to get to know what is actually expected of them when I saw this circuit.
How can I do an electrical analysis of this circuit (Kvl or Kcl)?
Image taken from the book RCA Receiving Tube Manual (http://www.tubebooks.org/tubedata/rc30.pdf) Page 7
Forward biased normal PN junction diode would act as a voltage regulator.so the voltage drop across the diode may be even 0.7V. when we decrease the load resistance(connected across the diode) the current drawn by the diode decrease and the voltage drop also reduces(when a lighter load is connected across the diode it would behave like a good regulator even when there are changes in the supply voltage this is known as LINE REGULATION;but when there is a change in the load it would not hold good LOAD REGULATION).
In other words the dynamic forward resistance of the forward biased diode would increase, if there is a reduction in the current flowing through the diode(the current flowing through the diode would reduce, when the load resistance is decreased)
If the same circuit in ideal model had both \$D_1\$, \$D_2\$ conducting, does that mean in constant voltage model \$D_1\$ and \$D_2\$ will conduct?
Need not be.
I see a few mistakes in the solution you have given here:
In the KVL, you missed one DC source. There are two voltage sources (+5V and -5V) in the loop.
The value of \$I_1\$ will be in milli-amps (0 ~ 1mA).
Voltage at node B is not \$5k \times I_1\$. It is \$5 - 5k \times I_1\$
Best Answer
Not sure what there is to analyze.
There's some current flow from plate to cathode (electrons are emitted from the heated filament/cathode), so the voltage across the output resistor, vacuum tube and ammeter add up to the B battery voltage, plus or minus (depending on which you pick as the cathode) some portion (maybe half) of the (much lower) filament voltage. It's more complex than it needs to be because of the directly heated cathode.
In practice often the cathode would be indirectly heated by an electrically isolated filament...
or the DC output would be taken from the center-tap of the transformer winding driving a directly heated cathode.
The vacuum tube has similar characteristics to a semiconductor diode, albeit with considerably higher resistance when forward biased, and less offset:
Diagrams from Vacuum Tube Rectifiers Alexander Schure.
You will find a similar characteristic curve in the RCA Receiving tube manual, where you likely plucked the image you used (please give credit for images on SE).