Electronic – Difference between NE555 and NE555xx

@Snickers, You can blame ;) it on Laplace who invented the formula for time to frequency domain transformation and Fourier for then deriving the frequency components.

I assume you are using the same formula fo S-K BPF?

H is gain and Q is shape factor fcenter/deltaF (-3dB) There are better filter designs and better sine wave designs too.

Here two matched Rf's control center F and one Rq controls Q.

You should not short circuit R1 (in your figure provided). Inside the 555, there is a BJT transistor that, when on, short circuits pins 7 (DISCH) and 1 (GND).

The purpose of that transistor is to discharge your capacitor, via R2, to ground, at the end of each cycle. If you make R1 zero, that BJT, when on, will short circuit your battery voltage. The low-resistance path will cause a high current through that BJT that may damage it (did they survive?). I can't find, in the datasheet, the rating for the current through that BJT.

You may make R2 very low (I'd say with a minimum of 100 ohm), but do not make R1 very low (not below 1 kohm, I would say). The capacitor gets charged through R1+R2, and gets discharged through R2. While the cap is being discharged, R1 sees your full battery voltage, and that's why it cannot be zero. You have three degrees of freedom (R1, R2, C) to choose charge and discharge times. If you want all your 555s to work in astable mode (i.e., as oscillators), use this formula to calculate the oscillation frequency, or to choose part values:

$$ f\approx\dfrac{1.44}{(R_1+2R_2)C} $$ Note also that, during the time (even short) while that BJT is short circuiting the battery voltage, your whole circuit sees no battery voltage, so it is no wonder that you don't hear anything, or that it does strange things. In fact, the IC losing its supply probably makes it stop keeping that BJT on, so the short circuit won't last long.

So, before trying to see why different 555s behave differently when their discharge BJT is abused that way, solve this issue.