Electronic – energy density comparison between inductors and capacitors

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The figure below is about energy density comparison between inductors and capacitors. This thesis concludes that capacitors possess greater energy density than inductors, as seen in the figure.

Source: Analysis of soft charging switched capacitor power converters by May, Ryan.

I would like to know how to get the data as in the figure. For example, say for one cubic millimeter what formula, which value of L, C, current, voltage do you use to get that data?

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Best Answer

Every inductor has a rated current, every capacitor a rated voltage. And of course their rated inductance or capacitance. And they come in a defined package where you can calculate the volume.

With capacitors you have to be careful though. Ceramic capacitors with some dielectrics will change their rated capacitance based on the voltage they are charged, so it's not quite as simple.

As an example, let's take a look at this inductor:

  • 10 µH
  • 5 A
  • 6.65 x 6.45 x 5.8 mm³ = 248.8 mm³

Neglecting the resistance of the inductor:

energy stored: \$E_{ind} = \frac{1}{2} L I^2 = \frac{1}{2} 10~\text{µH} (5~\text{A})^2 = 0.125~\text{mJ}\$

Energy density: \$0.125~\text{mJ} / 248.8~\text{mm}^3 = 0.5~~\text{µJ}/~\text{mm}^3\$

And for a capacitor let's take one of this series:

  • 47 µF
  • 25 V
  • 5.8 x 5.2 x 5.2 mm³ = 156.8 mm³

Again neglecting parasitics:

Energy stored: \$E_{cap} = \frac{1}{2} C U^2 = \frac{1}{2} 47~\text{µF} (25~\text{V})^2 = 14.7~\text{mJ}\$

Energy density: \$14.7~\text{mJ} / 156.8~\text{mm}^3 = 93.8~~\text{µJ}/~\text{mm}^3\$

So for these two the numbers of the study seem to hold up. I neglected the loss of parasitics, you can model these as well and get smaller numbers.