Electronic – Finding the voltage and current at t = 0 using Step Response

capacitorcircuit analysishomeworkshort-circuitstep response

The question that I'm trying to solve is as follows:

In the circuit shown below, the switch has been closed for a long time. a) What is v(0) or the voltage across the capacitor immediately after the switch is opened? b) What is i(0) and i1(0)?

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First, I calculated for the voltage before t = 0 using voltage division. I arrived at v(0-) = 4V. Since the capacitor voltage cannot change instantaneously, I assumed that 4V is the voltage at t=0.

Here's the tricky part. I'm asked to find the current at t = 0. By looking at the diagram, I am certain that the 1-ohm resistor is short-circuited, so I simply dismissed that and used Ohm's Law to find i1(0-) using v = 20 V and R = 4 ohms. In the property of short circuit, the i is equal to 0.

Are my solutions for i1 and i legal to begin with? I'm only confident with 4V as the voltage at t = 0.

Best Answer

Homework guidance:

Nobody shorts the 1 Ohm resistor, its end is opened so its current is stopped at t=0. Before t=0 there were 4A as your voltage division shows.

At t=0 the circuit changes. You have 4V in the capacitor, 20V in the source and a resistor between. The capacitor charges towards 20V starting from 4V. Find the formulas.