Electronic – For a crystal oscillator circuit, what effect would a series resistor have on the inverter input

crystaloscillator

In some application notes, there is a recommendation to use an external resistor in series with the OSC_OUT pin to reduce the power dissipated by the crystal, if necessary to do so. A good example is from AN2867 STM32 oscillator design guide called "R_Ext".

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Note there is never a resistor on the OSC_IN (EXTAL) leg in any application note and thus I never considered it for any transconductance calculation (Note 1).

So I've been a little bit thrown out by the S32K datasheet which explicitly shows an extra (internal) 280R resistor on the OSC_IN (the S32K calls the pin EXTAL) pin (p27, Figure 8):

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So, my questions are:

  1. Does this "resistor" have any effect on the transconductance (gain margin) of the circuit design? EDIT – Supplementary question: If it does affect the transconductance, how is this calculated?
  2. Is it likely to introduce any other effects that needs to get taken into account in the design?
  3. Would there ever be a reason to deliberately design in a resistor connected the inverter input?

Unfortunately, the 280R is 2-3 times larger compared to the ESR of crystals in the 16MHz range (in the order of 100R, e.g. this or this), so if it does indeed affect the transconductance calculation, the effect is non-trivial to the point where the circuit may refuse to oscillate.


Note 1:

The transconductance calculation I am referring to is the modified form that takes R_Ext into account as explained in the STM32 document referenced earlier:

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Part of the question is whether the resistor on OSC_IN needs to be included anywhere in this calculation.

Best Answer

The questions are about the 280-Ohm resistor on input. The picture clearly states that it is "ESD pad", and the value "280" likely represents the lump model for this pad cell.

  1. Does this "resistor" have any effect on the transconductance (gain margin) of the circuit design?

Yes, the resistor generally reduces overall gain of the amplifier (due to small parasitic cap on the internal inverter input), but the loss of gain is likely compensated in the inverter design.

  1. Is it likely to introduce any other effects that needs to get taken into account in the design?

Not really, see above.

  1. Would there ever be a reason to deliberately design in a resistor connected the inverter input?

This is just a model for ESD protection on the pin. Since the actual internal input impedance is likely in mega-Ohm range, the 280-Ohm shouldn't have much of impact. Even if the inverter input has 1 pF parasitic capacitance, the RC cut-off will be in ~3 Ghz area, or well outside the typical working frequency of 20-40 MHz

Therefore, the input resistor should be of no concern for the overall design.