Electronic – Foster’s Reactance Theorem – Reactance Increasing with Frequency

circuit analysisfilterreactance

I'm currently reading a text on analog filters (Zverev) that discusses Foster's Reactance Theorem in relation to passive circuits and I was thrown a little by the text that says: "Physically, this signifies that the impedance or admittance of the reactive network always increases in value when the frequency is increasing" (Pg 37 for those with the book).

Then the description of the theorem on wikipedia (wikipedia entry) has a similar line: "It is easily seen that the reactances of inductors and capacitors individually increase with frequency and from that basis a proof for passive lossless networks generally can be constructed".

I'm obviously missing something, but I always thought that the reactance of a
capacitor decreased with increasing frequency. What don't I understand?

Best Answer

Foster's Theorem uses reactance in the strict mathematical sense of the imaginary part of the impedance. This is of course signed. By convention, a capacitor's reactance is negative. At low frequency, it's large negative. At higher frequencies, it increases towards zero. This is opposite to the magnitude of the reactance, which of course decreases with increasing frequency. Read the whole of that wikipedia article carefully. What's wrong with the wiki article is it says 'It is easily seen ...', it can be seen, but not easily.

enter image description here

Image from the wikipedia article

These both show reactance increasing (becoming more positive) with frequency.