Electronic – Grounding unused leg of bussed resistor

This is a very complex issue, since it deals with EMI/RFI, ESD, and safety stuff. As you've noticed, there are many ways do handle chassis and digital grounds-- everybody has an opinion and everybody thinks that the other people are wrong. Just so you know, they are all wrong and I'm right. Honest! :)

I've done it several ways, but the way that seems to work best for me is the same way that PC motherboards do it. Every mounting hole on the PCB connects signal gnd (a.k.a. digital ground) directly to the metal chassis through a screw and metal stand-off.

For connectors with a shield, that shield is connected to the metal chassis through as short of a connection as possible. Ideally the connector shield would be touching the chassis, otherwise there would be a mounting screw on the PCB as close to the connector as possible. The idea here is that any noise or static discharge would stay on the shield/chassis and never make it inside the box or onto the PCB. Sometimes that's not possible, so if it does make it to the PCB you want to get it off of the PCB as quickly as possible.

Let me make this clear: For a PCB with connectors, signal GND is connected to the metal case using mounting holes. Chassis GND is connected to the metal case using mounting holes. Chassis GND and Signal GND are NOT connected together on the PCB, but instead use the metal case for that connection.

The metal chassis is then eventually connected to the GND pin on the 3-prong AC power connector, NOT the neutral pin. There are more safety issues when we're talking about 2-prong AC power connectors-- and you'll have to look those up as I'm not as well versed in those regulations/laws.

Tie them together at a single point with a 0 Ohm resistor near the power supply

Don't do that. Doing this would assure that any noise on the cable has to travel THROUGH your circuit to get to GND. This could disrupt your circuit. The reason for the 0-Ohm resistor is because this doesn't always work and having the resistor there gives you an easy way to remove the connection or replace the resistor with a cap.

Tie them together with a single 0.01uF/2kV capacitor at near the power supply

Don't do that. This is a variation of the 0-ohm resistor thing. Same idea, but the thought is that the cap will allow AC signals to pass but not DC. Seems silly to me, as you want DC (or at least 60 Hz) signals to pass so that the circuit breaker will pop if there was a bad failure.

Tie them together with a 1M resistor and a 0.1uF capacitor in parallel

Don't do that. The problem with the previous "solution" is that the chassis is now floating, relative to GND, and could collect a charge enough to cause minor issues. The 1M ohm resistor is supposed to prevent that. Otherwise this is identical to the previous solution.

Short them together with a 0 Ohm resistor and a 0.1uF capacitor in parallel

Don't do that. If there is a 0 Ohm resistor, why bother with the cap? This is just a variation on the others, but with more things on the PCB to allow you to change things up until it works.

Tie them together with multiple 0.01uF capacitors in parallel near the I/O

Closer. Near the I/O is better than near the power connector, as noise wouldn't travel through the circuit. Multiple caps are used to reduce the impedance and to connect things where it counts. But this is not as good as what I do.

Short them together directly via the mounting holes on the PCB

As mentioned, I like this approach. Very low impedance, everywhere.

Tie them together with capacitors between digital GND and the mounting holes

Not as good as just shorting them together, since the impedance is higher and you're blocking DC.

Tie them together via multiple low inductance connections near the I/O connectors

Variations on the same thing. Might as well call the "multiple low inductance connections" things like "ground planes" and "mounting holes"

Leave them totally isolated (not connected together anywhere)

This is basically what is done when you don't have a metal chassis (like, an all plastic enclosure). This gets tricky and requires careful circuit design and PCB layout to do right, and still pass all EMI regulatory testing. It can be done, but as I said, it's tricky.

If a pin is labelled N/C by a manufacturer then this almost always means that it should be NOT CONNECTED to anything.

ALL standard 8 pin xx555 timer IC have NO NC pins.
ALL pins have an assigned role.
Some should be left open circuit in some designs - but that is done as part of the design, as required.

Finding an NE555FE datasheet proved wondrous hard.
This page shows NE555FE and NE555F.
http://pdf1.alldatasheet.com/datasheet-pdf/view/17984/PHILIPS/NE555F.html

The NE555FE shown is a standard 8 pin package pinout and has NO NC pins.

The NE555F is an abomination which I have never seen before and which I did not know existed. If you have such an IC you should drive a stake through it's heart, wrap it in garlic, bury it at the nearest cross roads and/or send it to a local technology museum. I would also love a sample for my museum.

If you had one of these and insisted on using it then leaving the NCs disconnected would be safest. But, I'd advise using one of the many many many other 8 pin ones as this is an orphan.

I have seen pins which are labelled NC on a device's datasheet but which DO have internal connections. In some cases, connecting such to ground or supply is 'fatal'. Some modern LEDS have metallic connections on their thermal pad which MUST NOT be connected as if they were LED Cathode or Anode, as they are neither, but are not electrically isolated. Doing this seems very very unwise, but it's done.