Electronic – High Q peak in frequency response means what in time domain

frequency responsepassive-networks

Reading Linear Circuit Transfer Functions and one of the graphs got me curious.

I've recreated the circuit (series RLC) and plotted the frequency response for a Q of 7.

enter image description here

We have a peak of ~16.3 dB when Q is 7 @ 10Khz.

Can this value be used (16.3 dB) to accurately predict something in the time domain – such as the value of Q or how long the oscillatory decay would take, the amplitude of the oscillations etc.. ?

Added in case its relevent
enter image description here

Best Answer

Q is (among other definitions) the voltage gain at resonance, and a voltage gain of 7 times is $$20 * \log(7) = 16.9dB$$ which seems close enough as your cursor is clearly not actually on resonance (phase would be -90 not -93). So dB of resonant gain is trivially converted to or from Q.

Q gives you risetime and whether the circuit is over/under or critically damped in the time domain, as well as how well damped the ringing in an under damped circuit is.