Electronic – How does a lead acid battery accept more current when it is discharged than when it is charged if the resistance is higher when it is discharged

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I'm just trying to get my head around the above question. It doesn't seem to follow Ohm's law. Could someone please explain what I am missing in this?

Below is a chart I found of the changing resistance of a lead acid battery compared to state of charge, however, the charge acceptance is higher when it is discharged compared to when it is charged. How does this happen with a higher resistance that gradually gets lower?

I'm also assuming a constant charging voltage from an alternator.

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Best Answer

Not everything has to follow Ohm's law because not everything is a resistor. A battery is not a resistor. It is a battery. A typical beginner mistake when they first learn Ohm's Law is that they think everything follows Ohm's Law. I don't know why since it is clearly taught that Ohm's Law is for resistors, but I guess when the only tool you have is a hammer, everything looks like a nail.

Consider this: when a battery is discharged the internal battery voltage is lower, meaning there is a larger voltage difference between the battery voltage and the charging voltage. More voltage difference = more current. If that voltage difference is large enough the resulting increase in current can offset the decrease in current due to the higher resistance.