Can't seem to find the connection between the two. I have an error amplifier being fed with an analog signal. I'm varying the GBW of the op-amp to determine how does its GBW affect the rise time of the output. From my spice simulations, what i'm only getting is that increasing the bandwidth reduces the low and high frequency voltage ripples of the output. A higher bandwidth seems to give a faster rise time but I don't understand why is that so.
Electronic – How does an op amp’s bandwidth affect its rise time with a step input
frequency response
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1) Why does the magnitude Bode Plot of the response of a filter NOT approach Infinity at a pole?
Try looking at this picture and recognize that poles may exist as infinities in the bode plot but more usually they are "behind" it: -
2) In the attached image, why is Wp (Omega subscript:P) called the pole frequency when the denominator clearly does not become zero at that frequency?
The denominator becomes zero "behind" the bode plot. See above for relationship between bode and pole-zero diagrams.
3) Dealing in the S domain if a transfer function turns out to be 1/(s+2)(s+3) how can the Negative pole frequencies i.e s=-2,s=-3 be produced physically?What are the poles in this circuit?
They aren't physical at all - they don't exist except as a mathematical model to explain things. The only thing that exists on the 3D image above (bottom left) is the bode plot.
The AD8014 data sheet clearly shows that you will get significant peaking of the output signal when you have a feedback resistor that is this low. I would be considering a resistance that is at least 100 ohms.
If I increase the feedback resistance too high, the signal gets clipped, and I'm trying to avoid that.
At the moment with a 50 ohm feedback your peak signal is 900 mV. With 100 ohm it's going to be more like 1.8 volts so, given that the AD8014 is capable of producing \$\pm\$ 3.4 volts at its output, you should be OK. If the amplitude is too high for subsequent stages and causes clipping of those other stages then use a resistor attenuator after the front-end.
Best Answer
Rise time is inversely related to LPF (low pass filter) -3dB BW for a simple 1st order filter.
\$t_{10 ~to~ 90\text{%}}=\dfrac{0.35}{f_{BW-3dB}}\$
However, you cannot measure the 10% to 90% duration with a sinewave superimposed.
For a given open loop GBW product, BW = GBW / Gain closed loop.
BW can also be reduced with external CR filters with negative feedback.
For slew rate on large signals the active current limiter determines this into a specified reference cap. load
dV/dt= Ic/C