Judging from the other post, you are designing an experiment, where you want to demonstrate the resistivity at different temperatures. To do that, you need to know the temperature of the wire. You don't necessarily need to self-heat the wire with electricity.
You've chosen a comfortable range of temperatures: between +10°C and +40°C. You can touch this kind of temperature and it shouldn't hurt. However, the room temperature is usually +18°C to +25°C, so you would need some method of chilling to get +10°C.
I would suspend the wire in a container filled with non-conductive liquid**. The container can be large enough to measure with an IR thermometer. You can also have a thermometer immersed in the liquid. Have another container with warm liquid, and another one with chilled liquid. You can move the wire from one container to another and measure the effect. The temperature of the wire will equilibrate with the temperature of the liquid very quickly.
It could make sense to wind the wire on a plastic spool, being careful that the wire doesn't cross itself. Perhaps, you could lay the wire into the thread of a large plastic screw.
** Silicone oil from the drug store, perhaps. You could add some coloring to the liquid to make it look unusual. Deionized water could work too, it has high resistivity.
So, we characterize antennas using antenna pattern diagrams.
For example, the dipole has the following directivity pattern:
CC BY-SA 3.0, Link
If you imagine that dipole to extent vertically in the center of this image, you can see that the maximum amount of energy transmitted (or captured, if used in receive direction) is perpendicular to the dipole's length.
Now, you'd really want that main lobe to point in the direction of your source – otherwise, energy will just be lost. While you could certainly go and rotate your dipoles, you could also do what's been pretty standard in many high-power radar applications:
Beam steering.
Since I find this easier to understand when talking about transmitting antennas, I'll explain it as if we're sending power from base station to satellite – since everything (antenna, propagation) involved here works reciprocally, it directly applies to receiving power just as well.
You might have heard of the Huygens-Fresnel Principle. The idea is that if you've got a wave front, then you can model every point on that wave front as a source of "elemental" waves, extending in a perfectly circular fashion. Only the superposition of all these means that the wave front propagates in a straight line; in essence, they constructively interfere in that direction, and cancel out perpendicularly to that direction.
Now, let's revert that idea. If all we have to do to create a wavefront going in a specific direction is to generate elemental waves that are offset in time in such a manner that the ones closer to the direction we want to steer in are just enough set off in time that the beam "slants" toward them. This wikipedia image visualizes a phased array pretty nicely:
By Chetvorno - Own work, CC0, Link
All you need to have is adjustable phase delay elements for each dipole antenna (these are the \$\phi\$ boxes in the animation; \$\phi\$ is the commonly used letter for phase) and you can steer your angle \$\Theta\$ within wide boundaries, pretty much up to the point where the main beam is no longer perpendicular to your antenna array (which it would be if all the \$\phi\$ would be identical), but along the length of it.
As said, what works in transmit works in receive direction, too.
The question here really is how hard and expensive it'll be to build high-power, low-loss (because that's all heat that you'd need to get away - a problem in space), accurate phase shift units.
In the end, a large, mechanically adjustable, mesh dish antenna might be easier to realize, especially on the moon, where there's no storms against which that would need to be save against, as well as lower gravity. On the other hand, building an arbitrarily large array of dipoles can reduce the opening angle (and hence the efficiency in one specific direction) very very much (basically, the beam width as angle is antiproportional to the size of the array), and doesn't contain a single point of failure – so this might be a more scaleable solution!
Best Answer
Skin depth at 3GHz is only 1.2um, you'll need to consider that. I have no idea if this calculator is accurate, but it gives a resistance of 18.8 ohms for 100mm of straight 25um wire. However AWG 30 is more like 250um (0.25mm), so which is it? It would be more like 1.8 ohms for 100mm of 250um wire. Note that at 3GHz and this kind of diameter, the resistance is roughly proportional to the reciprocal of the diameter rather than the reciprocal of the diameter squared, since it's only a thin shell around the outside that's doing all the work.
In the case of 250um, that's about 50x as much resistance as the wire exhibits for low frequencies.
AC resistance will let you calculate the power dissipation, but calculating the temperature rise will not be easy- there may be tables used by transformer designers (since large transformers are often immersed in oil) but I doubt they go down to 250um let alone 25um.