Electronic – How to calculate a electrolytic capacitor based on current and voltage to have the smallest ripple

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I have built a circuit involving LEDs powered on 230V AC.

The LED current driver that is powered on 30V and contains 10 LEDs of 1W each.

One LED driver on 30V

10 of these modules are linked in series and are powered from 313V and it draws 80mA. The 313V is obtain with a bridge rectifier and a capacitor connected to the main line.
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  1. How do I calculate minimum capacity of the electrolytic capacitor based on current and voltage to have the smallest ripple?
  2. How do I know the wattage on AC line? I know that the DC wattage is around 25W (313V*0.08A).

Best Answer

How do I calculate minimum capacity of the electrolytic capacitor based on current and voltage to have the smallest ripple?

Smallest ripple is when capacitance is theoretically infinite. You have to accept that there will be ripple and you have to decide how much this ripple can be: -

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Taken from here

How do I know the wattage on AC line? I know that the DC wattage is around 25W (313V*0.08A).

The wattage taken from the AC power line is probably a few percent more than what is consumed in the DC circuits you have attached. Power in = power out + losses in rectifier and smoothing capacitor.

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