I have a 1.25V 2Ah battery and I'm trying to calculate a equivalent capacitance with rated voltage of 2.7V for each of those batteries. This is what I did:
Work of Battery = \$1.25V \cdot 2A \cdot 3600s = 9000J\$
From the capacitor work equation:
$$W = 0.5 \cdot C \cdot V^2$$
$$9000J = 0.5 \cdot C \cdot 2.7V^2$$
Is this correct?