Electronic – How to calculate RPM using frequency

frequencyinverterrpmvfd

I am working with VFD (CT-2002ES-A75). It shows output frequancy on it's seven segment display. However It has a parameter(Cd46 on page 27 in the manual) for display the current RPM of the motor.

For display the current RPM need to enter some factor as parameter input.
How to calculate that scaling factor for my motor?

This is the nameplate of the motor that controlled by the VFD.
Motor is connected as star system. Working on 230VAC supply.

Motor nameplate

Best Answer

  • If a motor has two poles it will rotate once per mains cycle. At 50 Hz this will be 50 x 60 = 3000 RPM.
  • If a motor has four poles it will rotate half a revolution per mains cycle. At 50 Hz this will be 50 x 60 / 2 = 1500 RPM.
  • If a motor has six poles it will rotate one third of a revolution per mains cycle. At 50 Hz this will be 50 x 60 / 3 = 1000 RPM.

This can be generalised as RPM = 120 x f / poles.

Therefore # of poles = 120 x f / RPM.

Since induction motors slip the full-load RPM will be somewhat less than the calculated speed. From the rating plate we can see that the min -1 (revolutions per minute) is 930 to 950 at 50 Hz. This is just below 1,000 RPM so it must be a six-pole motor.