I've been try to solve this circuit for hours and have no idea on how to find the load voltage U_s
.
I tried applying the Thevenin theorem to find the equivalent Thevenin voltage (using the voltage divider rule => E_Th = 6V
) and also the Thevenin resistance (we take R_s
and R
in parallel and the result is going to be 5k (ohms)
).
I don't know what to do next. Should I replace the diode with an open circuit because it is reverse biased? After that, is it okay if I say that the voltage on the cathode
is V_C = E_0 = 3V
, and compute the voltage on the anode
using the voltage divider rule?
Best Answer
As was suggested in your previous question, redrawing the circuit may help:
OK. So that would result in the following circuit:
From that, what is your reasoning regarding \$I_D\$?