Electronic – How to convert current source to voltage source when to current sources are in parallel

Generally power cannot be found out separately by using superposition principle, since power is parabolic with reference to current.

When you find the power delivered to an element of impedance Z through which current I flows, the answer is (I^2)*Z;

When you use superposition, then you get current due to both sources individually as I=I1+I2; When you calculate the power individually, due to the individual sources, you would be getting P1=((I1)^2)*Z and P2=((I2)^2)*Z; hence you would calculate the total power to be P=P1+P2=(((I1)^2)+((I2)^2))*Z; which is incorrect since the total power is P=(I^2)Z=(((I1)^2)+((I2)^2)+2(I1)*(I2))*Z;

What i'm unsure about is; although on the the supply voltage source states 2v, 500Hz at 0 degrees, with the capacitor in the circuit i am under the assumption that the voltage source phase angle will be shifted as a result?

If the voltage source is an ideal voltage source, then its output voltage (magnitude and phase) is independent of the load. So there's nothing to calculate.

If the voltage source is not an ideal source, then you need to know its output impedance. This impedance is essentially another element in series with the source and the applied load. You'd use the voltage divider rule or just include the output impedance in your nodal analysis model to determine the phase at the output of the source.