Electronic – How to make a chip with lots of pins in Logicworks

I figured this one out. It turns out you have to create your own bus port inputs and outputs. It's fairly easy:

Open a new file for creating a device symbol. In Device Symbol Editor, Choose “Set to primitive type” in Options-> subcircuit/part type and then choose Port Connector. The symbol will then be of Type Port Connector. Create a number of pins for a bus by choosing Option->Add pins with, for example, INPUT[A0..A3] for a four-bit input bus that has signals A0 to A3. The signal names must match those that the bus is to be connected to. Therefore each bus port connector can only be used once to connect signals with same names. A bus internal pin can be either output or input or bi-directional. Set pins on a bus to be output pins if the pins are to be connected to inputs of a sub-circuit. Draw a bus symbol that can be any shape you want. Select a bus pin from the symbol palette and place it on the bus symbol. There are four bus pins, one for each side of the bus symbol. A screen capture on the right shows how a 4-bit input bus port can be created. Notice that the pin functions are designated as Output, although the bus port is an input bus port. Make sure the pin directions and the number of pins match the intended application. Save the port connector symbol to your own library.

Rather than try to use the same pins as both analog inputs part of the time and digital output(s), I would do the following:

Add an 8-channel analog mux to the driver board, such as the HEF4051B. The output of the mux will then go into one of the analog input lines currently going to the MCU board. Tie the enable lead \$\mathsf{\small \overline{\text{E}}} \$ to ground (always enabled).

Reconfigure the remaining seven analog inputs as digital.

Use three of the seven digital lines to select the 1 of 8 channels for the mux.

You now have four digital lines available between the MCU board and driver board.