Electronic – How to power a white LED from batteries

ledvoltage-regulator

I would like to power a white LED from batteries.

The LED I'd like to use has a forward voltage of 3.3V, the datasheet specifies the voltage range from minimum 2.8V to maximum 3.8V.

My idea is to use 1.5V AA or AAA batteries to power the LED, I don't want to use Lithium batteries for this project. I'm open to alternative suggestions though, if they would fit the project better. I'm aiming for a long battery life though, so no button cells.

If I use 2 batteries, I get 3V – this would be in the allowed range, but very close to the lower limit of 2.8V. As soon as both batteries drop to 1.4V, I'm out.

If I use 3 batteries, I get 4.5V and therefore a much greater voltage range that I can work with, but I have to get rid of something between 3 * 1.5 – 3.3 = 1.2V and 3 * 1.3 – 3.3 = 0.6 V.

I see several options here:

  • Just go with a fixed resistor and drop 1.2V. Works fine when the batteries are fully charged, LED will become dimmer over time until the batteries reach (2.8 + 1.2) / 3 = 1.33V

  • Use a buck converter to convert 4.5V to 3.3V. I'm not very experienced with buck converters and all items that my local electronics supplier has stocked that have a output voltage of 3.3V need at least 6V input voltage. I don't mind cramming more batteries in there, but does that give me any advantage?

    I guess that using a buck converter should give me a steady supply of 3.3V as long as the converter has any input voltage above a certain treshold, so I'd not experience any LED dimming. Is that correct?

  • Use a linear regulator. Researching my question I found some answers that said something like "a linear regulator is fine, because you don't have much voltage to drop". Usually those questions where about micro controllers though and had a power consumption of some hundred µA. Would using a linear regulator work with a LED that has a power consumption of 20 or 30 mA?

Can you give me some advice which solution I should follow or am I going in the totally wrong direction? Would those solutions still work if I would want to power two or three LEDs with identical specifications?

Best Answer

Try this little circuit for a start. It runs from near-empty AAA batteries.

schematic

simulate this circuit – Schematic created using CircuitLab

Well, how does it work?

  1. In the beginning, both the transistor and the LED are shut off.
  2. A small current flows through the lower leg of the coil into the base of the transistor.
  3. The transistor turns on the C-E path. Now a much higher current flows through the upper leg of the coil and the collector of the transistor.
  4. Because the upper and lower leg of the coil are magnetically coupled, the current cannot flow in opposite directions in both legs. The small current into the transistor base runs dry.
  5. The transistor shuts off again.
  6. The current running through the coil cannot be shut off in an instant! That's why the coil increases the voltage at its terminals to sustain the current. That voltage is added on top of the source voltage.
  7. Eventually, the voltage is high enough to bring the LED into conduction (and lighting it up in the process.)
  8. The voltage of the coil decreases again.
  9. The LED shuts off again and the process restarts.

Congrats. You have built and understood the simplest boost converter of all.

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