Electronic – Initial pluse from schmitt trigger switch debouncer

debounceschmitt-trigger

I want to use a momentary, normally open, SPST switch to act as a clock pulse on 16×2 character display. Of course, my switch has some bounce so I was looking at debouncing circuits and I always see the same one that uses an RC circuit in conjunction with a schmitt trigger inverter. For example, this one (which includes an extra diode that some folks use and some don't):

RC debounce circuit

The problem I see with this circuit (if I understand it correctly) is that the capacitor starts out at 0v, then charges up, which should result in the circuit putting out a high-to-low transition when it powers on the initially.

Am I misunderstanding this, or do most folks not care about that initial transition?

Best Answer

The cap charges through R1 and the diode when the switch is open, and sit at a diode drop below Vcc, producing a LOW on the output of the schmitt inverter. So yes, the output is high until the cap is charged. Any system using this will need to deal with the initialization transient.

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