Electronic – Isolated DC/DC flyback/SEPIC

dc/dc converterflybacksepic

As far as I understand the flyback topology, it can be used in both buck and boost converters.

What I am not sure about is: Does it also work for the case where buck-boost is needed, i.e. \$V_{\text{in,min}} \leq V_{\text{out}} \leq V_{\text{in,max}}\$?

I think it should, but googling the topic immediately leads to the SEPIC converter. Also, I know that isolated SEPIC is possible, but I rarely see design examples.

Could you give me some idea on what topology to use for the specific case of:

\$9 < v_{\text{in}} < 24 \text{V}\$ for \$v_{\text{out}} = 12 \text{V}\$ at 1 A, galvanically isolated

Best Answer

Yes, a flyback converter can masquerade as a buck-boost converter: -

enter image description here

This one from LTI also negates the need for an opto-isolator by sampling the back emf in the primary - that back emf is indicative of the secondary voltage so it's quite a useful little device.

Compare that with a buck boost offered also by LTI: -

enter image description here

There are advantages and disadvantages with the buck-boost. Firstly there is no output isolation but it doesn't require a minimum load and will be 5% or so more energy efficient.

So, you may ask, how does the flyback converter generate higher output voltages than the input when it appears to use a step down transformer. This is acheived by PWM effectively altering the transformer turns ratio (to put it crudely).

Think of the output load as requiring so-much power to acheive a certain regulated output voltage; the fly-back design transfers energy stored in the primary to the secondary each switching cycle and that energy transferred, multiplied by the number of cycles per second = power transferred. In other words it doesn't work like a normal transformer because you can, on the face of it, have what seems to be a step down ratio yet a higher voltage is produced due to the flyback effect.

Clearly, if you want a lower voltage on the output compared to the input you want your output winding to be low inductance so that it can supply more current to the heavier load but, it's not a hard and fast rule.