Electronic – KCL / KVL Circuit Analysis

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I have a question regarding using KCL / KVL to analyse the circuit below to find all currents and voltages.

My question is : When performing KCL at the top centered node, what way should I assume that Iz is flowing? Should I assume Iz is flowing with the arrow (out of the node) that is given in the question, or assume it goes into the node based on the voltage drop of -2V over the series resistor?

What is confusing me is when I work out my Iz current, I get a positive value flowing into the resistor, but that doesn't seem correct with a voltage drop of -2V?

I am happy to post my full solutions if anybody would be happy to check them?

Thanks for any replies.

Thanks for the great answers everyone.

Yeah I think my mistake was assuming they were pure resistors for some reason but now I see how I could actually get negative voltage drops over the 'black boxes'. I think that was what I was struggling with.

Anyway here my solutions for all unknown voltages and currents for the same circuit below:

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Best Answer

If the diagram is to be believed....

By simple inspection Iz must be 2 amps and, it must be flowing in the direction shown by the arrow and, if it produces -2 volts across the component top-right then that component has a resistance of negative 1 ohm.

Also, by simple inspection Iy must also be 2 amps and therefore the middle vertical component must be positive 2 ohms to produce 4 volts across it.

This makes Ix equal to 4 amps.

And this ties in with the middle left current of 1.5 amps and the bottom left current of 2.5 amps joining to make Ix = 4 amps.

So, I think the diagram is to be believed.

When performing KCL at the top centered node, what way should I assume that Iz is flowing?

You can assume it flows in any direction and, after doing the analysis it either is positive or negative with negative implying it was flowing in the opposite direction you initially assumed.

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