I have a vacuum tube that has 9 pins. 3 of the pins are heaters and aren't connected to the PCB I'm designing, meaning only 6 pins need to be connected to the PCB. The Tube itself sits in a panel mounted socket that's not part of the PCB.
I'd like to use a 6 position screw terminal block on the PCB to run wires to the tube socket.
I assigned a 6 position screw terminal block footprint to the tube in the schematic, but only 3 of the pins are showing as being connected in the PCB editor.
How do I assign the tube pins 6,7,8 to the footprint pins 4,5,6?
EDIT
Adding some pictures:
So here is Unit A and Unit B of the tube on my schematic. Notice I only use pins 1,2,3 and 6,7,8. I actually lied in my first post, pins 2 and 7 aren't connected to the PCB either, so really I only need a 4 position terminal block, but the question still is the same…
I assigned a 6 pin terminal block as the footprint. In the PCB editor this is what I see. Instead, I want all the pins of the terminal block being used:
Thank you!!
Best Answer
You need to design either:
This means create your own footprint library, or your own schematic component library. That's a process with lots of clicks, but not actually difficult (you can easily create new footprints/parts from existing ones).