Electronic – LM2940 low dropout voltage regulator specs

voltage-regulator

I was looking at the LM2940T-5.0 low dropout 5v voltage regulator spec sheet and i'm puzzled!
The dropout voltage is listed at 0.5v for a 1A load, at 0.15v for a 200ma load, and at 0.1v for a 100mA load.
Yet the minimum input voltage is listed as 6.25V for a 5V output!

Why wouldn't the minimum input voltage be 5.5v for a 1A load or 5.15v for a 200mA load?

The reason i'm asking is that i want to use a 6V input to get a 5V output for a load of about 100 or 200mA. 6V is of course < 6.25v, but it is >> 5.15v. Will this work? What am i not understanding here?

Also (minor), is there any difference between "dropout voltage" and "input-output differential"? The reason i'm asking is that there are side-by-side plots on page 8 of the TI spec sheet that use these two different terms, but the values in the plots seem 100% compatible!

Best Answer

I will assume you are referring to this datasheet.

Under Section 6.5 Electrical Characteristics, the minimum input voltage is specified for 5mA <= Iout <= 1A over the recommended operating temperature range. You must give it 6.25V minimum for it to be able to provide that range of current over the temperature range.

The comparable number for 100mA is 5.35V (200mV max dropout + 5V + 150mV) over the temperature range . It would be more for 200mA. You don't really want to go right down to the minimum dropout, which is why it's specified with a bit more than the absolute minimum input voltage.

This is generally true of all linear ICs- if you run it right up against the maximum limits (for example, a rail-to-rail amplifier right near the supply rails) the performance will deteriorate noticeably.