First, you WILL need to put a divider, or an amplifier with a gain of .05 before the LM386.
The minimum parts schematic you reference in the datasheet will work for you. The part has a DC offset of Vcc/2 at the output. The purpose of that matching network is two-fold. First, it keeps the DC contained to the output pin, away from the speaker. The second function is matching. Follow that schematic and you should be fine. The only thing to add that isn't on the schematic is a decoupling capacitor at the power pin. If you don't add one, you will get some very weird artifacts at the output.
The part will do 17 kHz easily, and can go out over 100 kHz.
I would try to find 12V to power it though. The part was originally designed for automotive use.
Assuming, for quick analysis sake, that the diodes and emitter-base junction each have 0.7V across, this leaves 0.7V across R5. The emitter current for Q2 is then:
$$I_{E2} \approx \dfrac{0.7V}{39 \Omega} = 18mA$$
Thus, the first thing you should is check to see if you do in fact have this. Measure the voltage across the R5 and use Ohm's law to calculate \$I_{E2}\$. If it is "in the ballpark", the bias circuit is working as designed.
without them, Q2 goes into saturation, and is basically bypassed - the
amplification is done by Q3 alone
Q2 isn't configured as an amplifier in this circuit, it is an active load (current source) for Q3. Note that the voltage at the base of Q2 is effectively constant while the audio signal from Q1 is applied to the base of Q3.
Essentially, Q2 supplies an approximately constant current "down" out of the collector.
I've simulated this circuit with pSpice and it doesn't work well at all which doesn't surprise me for a number reasons. The output stage is highly non-linear but there's no DC or AC feedback around it. The collector voltage of Q3 is thus poorly controlled.
In fact, when I simulate the operating point, I find that Q3 is in saturation.
To simply address some of the problems with this circuit, I added two resistors:
- An emitter resistor for Q3 to add local feedback
- A resistor between the collector of Q3 and the emitter of Q1 to
provide both DC feedback, to set Q3's collector voltage at about 6V,
and AC feedback to set the open-circuit small-signal gain to about 20dB.
By adding these resistors, I need to change the value of R7 to 220k. The values I picked for the added resistors and R7 are not necessarily optimum and were found by "playing around" with the values and simulating until I got what I wanted.
A more rigorous derivation of the gain and operating point dependence on these resistor values would be fun but I honestly don't have the time at this moment but... maybe later.
Below is a transient simulation with 1Vpp 1kHz input:
Best Answer
Voltage in x gain = voltage out. The current that flows in the headphones is V/Z where Z is impedance of headphones. Z is a little frequency dependent.
Input current to amplifier is voltage in/ input impedance. Input impedance is usually 1k to 1Mohm (generalism warning).
Yes, you need to know the input voltage. You need to know the maximum it can attain and the nominal RMS value that would produce (say) a comfortable nominal listening level in the headphones. The headphones will have a SPL (sound pressure level) characteristic that you need to research. Also research what would be a comfortable SPL level. You then begin to know what the voltage level ought to be across each speaker in the headphones.
You might also consider hard-clipping to prevent acoustic shock (should your amplifier be capable of delivering much higher voltages to the head phones).