Electronic – Need help understanding why noise temperatures are added, but real temperatures aren’t

low-noise-amplifiernoisetemperature

Wikipedia says:

In a wireless communications receiver, the equivalent input noise temperature \$T_{eq}\$ would equal the sum of two noise temperatures:

$$T_{eq} \ = \ T_{ant} \ + \ T_{sys}$$

I understand that these values of \$T\$ are related to temperatures, but they are not themselves actual temperatures that one measures with a thermometer.

If I put a 273K ice cube in my 357K coffee (no pun intended) I'd get cooler coffee, not 630K coffee. The same applies if they are two streams of fluid mixing rather than static objects.

In another setting; at given frequency, the noise power of an external radio source, like a blackbody source, would scale as the fourth power of temperature, not linearly.

I need help understanding why noise temperatures are simply added, even though in the real world the last thing we'd think of doing is adding two temperatures together.

Best Answer

I think this is a case of just confusingly worded Wikipedia articles. That passage would seem to suggest that if you ever have two noise temperatures then you can just add them together. As you've aptly explained, that doesn't make any sense.

Rather, \$T_{sys}\$ is a figure of merit that's calculated by measuring the noise added by some component. The input noise is \$T_{ant}\$. After passing through some component, the noise will be \$T_{eq}\$, which must be equal to or greater than \$T_{ant}\$. And the difference is \$T_{sys}\$, by definition.

If \$T_{sys} = 0\$, you have an ideal component which adds no noise.

If \$T_{sys} \ll T_{ant}\$, you have a realistic component which adds only negligible noise, and the signal to noise ratio (SNR) is not significantly decreased. Like a good LNA.

Thus \$T_{sys}\$ makes a convenient figure of merit: by comparing it with the input noise temperature it's easy to see how relevant the noise added by this component will be. If the input noise is already high there's not much reason to spend more money on components with a lower \$T_{sys}\$.

By using a LNA with a very low \$T_{sys}\$, the signal and the noise can be amplified with a minimal decrease in SNR. Once that amplification is done, the input noise (\$T_{ant}\$) is much higher (because all the noise power was amplified), so now all the components that follow can have a much higher \$T_{sys}\$ (and thus lower cost) without having an unacceptable impact on SNR.