For your consideration, I have this Astable-multivibrator via a classic Op-Amp Schmitt Trigger delivering a square signal (here 1.82Hz).
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I am fine with the circuit with SW1 open as C2 is basically in Series with C1 making CT = 5uF.
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However, I am not sure about the effect of SW1 being closed.
Can someone enlighten me?
Figure 1. Switch Open
Best Answer
With the switch on, it would basically increase the RC time constant and increase the time. It could be considered C2 shorted and the vibrator would continue with the frequency formed from R3, R1 and C1