I’m wondering if I’m making the right approach when I’m trying to calculate the power consumed by the diode in the circuit.
Here is the problem:
So my approach is:
Power loss by diode
$$V_f \times I_f$$
where
\$V_f\$ = Diode forward voltage drop.
\$I_f\$ = The current flowing through the diode.
So the first thing I did was to calculate the current
$$I = V/R = 5/1000 = 5 mA$$
And then I use
$$
V_f \times I_f= 2 \times 0.005 = 10 mW
$$
Is this correct?
I feel like there is more to the problem with the fact that it states ”red color light”. Should I check on a sheet or similar?
Best Answer
I think that you have neglected the voltage drop across the diode which limits the current.
My solution is : $$ \because V_{R_1}=V_0-V_f=5-2=3\,\text{V} $$ $$ \therefore I_f=I_{R_1}=V_{R_1}/R_1=3/1000=3\,\text{mA} $$ $$Power Loss =V_f\times I_f=2 \times0.003=6\,\text{mW} $$