Electronic – Simple DC voltage scaling with two ranges, lower range voltage limited

For working with power conversions rather than signal -

You can use various integrated circuits for this job, they're commonly referred to as Dc to DC converters, there's also a range of ways to do the conversion such as Charge pumps.

Here's a bunch of different DC to DC converters they have various different current ratings, some step the voltage up, some step down and others convert between positive and negative values.

This is a nice charge pump IC that can double or invert a voltage with the minimum of external components. You could even use a 555 timer to convert a voltage to a negative

Hope this helps.

A 741 cannot do what you ask. Find a 741 data sheet, and look for "output voltage swing". You will see that, for instance, at a power supply of +/- 15 volts it will allow an output of ~+/- 12. In other words, the lowest output voltage specified is never anywhere near the - supply. In your case, the - supply is ground, so you cannot expect the 741 to give you a zero volt output.

Just as bad, please note that the 741 is specified (typically) for a voltage supply of +/- 15 volts. It really wasn't intended for any other situation.

The simplest solution to your problem is to get a "rail-to-rail output" op amp. Also check to be sure that it will handle a supply voltage of 12 volts (some will only go to 5 volts - or less). If that doesn't appeal to you, you'll need to provide a negative Vee.

With the op amp sorted out, your circuit is not a good design. Try

^{simulate this circuit – Schematic created using CircuitLab}

EDIT: Please disregard the previous schematic. I had misread your requirement. Your circuit still won't work. For instance, if you provide a V- of about -16 to -20 volts, at 9 volts the circuit will produce -9.34 volts, and at 11 volts the output will be -12.61 volts.

Having said that you want the 9 to 11 volts to scale to 0 to 5 volts, you don't specify which value scales to which output value. For the requirement that 9 volts produces 0 volts, and with no negative supply,

^{simulate this circuit}

does the job, while still using the 2 volt reference.