Electronic – Simplest remote IR

infraredwireless

What I need is: when I turn on a IR led, a receiver circuit in the other side would have 5V or 0V depending on the state of the transmitter. Simple.

I have a IR transmitter and a photo-diode for receive, those used on every IR control and receiver. I don't know how the photo-diode works so how should the circuit be? Should I use a transistor configured in saturation / cut-off working with the receiver?

Feel free to recommend me. Thanks

Best Answer

Phototransistor configured as an inverter:

5V ----+
       |
       /
       \  47k
       / 
       |
       +----- Logic output (inverted)
       |
  \   /
  \  |    NPN
      \>  Phototransistor
       |
      ---
       -

A phototransistor is like a photodiode, but has a significantly increased gain. So when light shines on it (or IR, if it has an IR filter) it will pull down the output, conducting a few mA. A photodiode could do the same job, but you'd need a much greater (x100-1000) resistor, and this might be overwhelmed by the any load impedance.

You could put another inverter on the output to get a logic signal of the correct polarity (or to buffer it, as it won't take much load current.) Here is one possible inverter circuit:

          5V ----+
                 |
                 /
                 \  10k
                 / 
                 |
                 +--- output
                 |
          10k   /
Input ---/\/\/--|   NPN
                \>  2N3904
                 |
                ---
                 -