Electronic – Single phase rectifier

diodesrectifier

can someone please help me to solve this problem?
This is the scheme: enter image description here

I can't recognize where the voltage can turn because all the diodes are blocked.

Best Answer

enter image description here

By simply redrawing the circuit in a more conventional way it is easy to see that it is a full wave rectifier circuit. If transformer centre tap is taken as 0V then the joined anodes of the diodes form the negative voltage output terminal.

I've never heard the term "charge fortement inductive' but it sounds like some form of on-line translation of an inductive/capacitive smoothing filter.

enter image description here

Direction of current. (added to answer comment)

enter image description here

Consider each half cycle of the input. The dot notation gives the phase relationship between the input and outputs. The output at cathode D1 will be more positive than the centre tap which will be more positive than the cathode of D2. Conventional current flows from positive to negative and the diode arrow symbol shows that direction. On the positive (input) half cycle the cathode of D1 is always more positive than its anode so no current can flow through it. D2 cathode is always more negative than its anode so current can flow through it and complete the circuit path.

On the negative half cycle input the output voltages are reversed and current can only flow through D1.

The LOAD will experience current flowing in the same direction on each half cycle.