Electronic – Switching multiple outputs with a single input

Use the switch to control analog switches. The switch then just needs to be SPST with a pullup resistor. This will be the control signal to the analog switches. One switch line can easily drive many CMOS inputs, so fanning out to six won't be a problem.

Analog switches are sometimes called "bilateral switch" because, unlike "digital muxes", they work just as well in both directions -- much like a relay. Sometimes I use an analog switch to connect the output of one chip to either one of two "input" lines (with pull-up or pull-down resistors to set the "other" line to the appropriate state), much like a digital demultiplexer. Sometimes I use an analog switch to connect the input of one chip to either one of two "output" lines (no resistors are needed for this case), much like a digital mux. Sometimes I use an analog switch to connect a bidirectional line like the I2C data line.

Analog switches act much like relays, except (a) they can't handle much current -- some handle 25 mA, others can handle only 10 mA. (b) they can handle only a limited voltage range -- some handle 0 to +15 V, others handle only 0 to +5 V. (c) they are lower cost, can switch far more rapidly and more often, and require much less power than relays.

(This is a minor tweak of the answer from Olin Lathrop).

Some parts I would consider:

• 74HC4066 quad SPST bilateral analog switch
• 4053 triple SPDT analog switch
• 74HC4353 triple SPDT analog switch
• 4052 dual SP4P analog switch
• 74HC4852 dual SP4P analog switch
• 14551 quad SPDT analog switch

You might be able to do this with two chips, and perhaps some pull-up or pull-down resistors.

What you're asking about is called fan-out.

You need to compare the output current capability of the 40174 with the input leakage current of the 4066 control inputs.

I looked at datasheets for some 40174 and 4066 parts from NXP and the 4066 had an input leakage spec of 1 uA, while the 40174 had an ouput drive capability (worst case is sinking current for low output) of 0.4 mA. So you can conceivabley drive quite a few 4066 loads from a 40174. But you didn't say exactly which part numbers you're using, so you need to check your own datsheets.

Also be aware that the more you fan out, the slower the switching transient will be, so you also need to consider the capacitive load of your 4066's and your required switching delay. The 4066 load is about 7.5 pF (max). With 0.5 mA drive this gives a 66 V/us slew rate (very roughly), divided by the number of loads. If you want to switch 5 V in less than 1 us, you can't drive more than about 13 loads. If you want to switch very frequently (e.g. 10,000 switches per second or more) you need to start looking at power handling capabilities of the '174's as well.

Edit: looking at the TI datasheets you linked, your parts have similar specs to the NXP parts I looked at.