One of the several important advantages of the three-phase, a.c. induction motor is the grace with which it delivers a variable torque. You did not mention the motor's number of poles or whether your power was of the 50-Hz, Old World kind or of the 60-Hz kind used in the New World. In the Old World, the maximum (not minimum) speed of a typically configured induction motor is 3000 rpm, and this only if it is a two-pole motor. Four-pole motors are more common: their maximum speed in the Old World is 1500 rpm.
For the sake of answering, let us suppose that you are in the Old World and that your motor has two poles: maximum speed, 3000 rpm. (If in the New World, you can scale this answer's speeds by [60 Hz]/[50 Hz] = 1.20: maximum speed, 3600 rpm.)
For moderate values of torque—usually up to about 115 percent of the motor's full rated load—the motor's speed will decrease slightly and approximately linearly as the mechanical load to which the motor delivers power demands torque. For example, if the motor turns at 2800 rpm at full rated load, then it will turn at about 2850 rpm at 75 percent of full rated load, 2900 rpm and 50 percent, 2950 rpm at 25 percent, and (almost) 3000 rpm when unloaded. At loads greater than 115 percent, the motor's speed will decrease more than the linear model predicts, until the motor's breakdown torque is reached (the exact value of breakdown torque depends on the motor, the ambient temperature and other factors, but 200 to 230 percent of full rated load might be a typical figure). At breakdown torque, the motor will spin down to a stop, thenceforth acting as an inductive winding and delivering the motor's rated locked rotor or starting torque to the load.
I give all this detail for three reasons. First, because it may contain the answer you seek. Second, to explain why there is no single torque, but are many torques involved. Third, to convey the crucial concept that, within the motor's operational domain, it is the mechanical load, not the motor, that determines the torque.
If you really need to measure the actual torque accurately under specific conditions, then use a dynamometer. However, if an approximate indication of torque is all you need, and if you are operating in the motor's normal, spun-up state, at no more than 115 percent of full load, then you can approximate the torque pretty accurately from the motor's measured speed and its nameplate data, using the linear relationship described. The approximation is so much easier than the dynamometer that I would recommend the approximation in most cases.
Note: A few, unusual three-phase a.c. induction motors do not have any breakdown torque. In other words, for a few induction motors, the locked-rotor torque is the maximum torque the motor can deliver. In the United States, such motors usually read "Design: D" on their nameplates. This is probably not the case for you, but I thought that I should at least mention the matter.
Usually in college laboratory they connect brake drum and spring balance meters with motor's pulley to measure the force. (you may refer this image below i attached)
While running test you need to measure the speed using tachometer and spring balance force.
And need to find the radius of brake drum .
Torque= force*distance
Torque= (difference between spring balance )* (radius of brake drum)
In industires they may use test benches they can easily do this
Best Answer
The curve can be drawn using the following per-phase equivalent circuit:
V1 is the line-to-neutral voltage. The power source is assumed to be wye regardless of the actual configuration. R1 & X1 are the stator resistance and stray reactance. R2 & X2 are the rotor resistance and reactance referred to the stator. The per-unit slip, s is the slip RPM divided by the synchronous RPM. The magnetizing branch, between a and b, is neglected. The effect of the rotor bar shape on X2 and R2 is neglected.
The following equation gives the torque developed in the rotor for assumed values of s. The actual torque available at the shaft would be reduced by the torque lost to friction and windage (aerodynamic drag). q1 is the number of phases. Omega is the stator power frequency.
The images are from Fitzgerald, Kingsley, Umans Electric Machinery 4th ed.