Electronic – Transformer Design: How to set an N1/N2 ratio by means of selecting winding inductances

designinductancetransformer

I'm trying to simulate a transformer by using a circuit simulation software. In my requirements sheet, three specifications are given for the transformer:

  1. Maximum power (\$P_m\$) of the transformer will be 4VA.
  2. Magnetizing inductance (\$L_?\$) will be 30\$\mu\$H.
  3. \$\frac{N_1}{N_2}\$ ratio will be 4.

(I don't know what "magnetizing inductance" is. Is there a term like that? Can it be mutual inductance (\$L_m\$)? Are \$L_m\$ and \$L_?\$ the same parameters?)

The turns ration must be a function of these parameters, isn't it?

Like:

\$\frac{N_1}{N_2}=f(P_m, L_1, L_2, L_m)\$

Where;
\$L_1\$: Inductance of the primary winding.
\$L_2\$: Inductance of the secondary winding.

My simulation software does not allow me to directly set \$\frac{N_1}{N_2}\$ ratio. Instead, it allows me to set the \$L_1\$, \$L_2\$, \$L_m\$ parameters.

So, my question is, how do I indirectly set the turns ration (\$\frac{N_1}{N_2}\$) by choosing \$L_1\$, \$L_2\$ and \$L_m\$ parameters?

Best Answer

It sounds like you're dealing with a SPICE simulator.

In SPICE, you define a transformer as a coupled inductor, with the following ratio:

\$\dfrac{N_1}{N_2} = \sqrt{\dfrac{L_1}{L_2}}\$

There's also a coupling factor K that comes into play.

The magnetizing inductance of a transformer is the inductance you measure across the primary winding with the secondaries open-circuit (floating). It's a function of the core material and geometry, air gap and number of turns.

Your \$L_1\$ and \$L_m\$ should be one and the same.