In my last question,
Transistor current control with positive feedback differential amplifier I made a mistake.
The actual circuit seems like this
I am beginner in linear electronics and I am very interested to know how the output current of transistor is being controlled with Vin voltage.
1) OpAmp is being used as Open Loop gain Amplifier ? Vout = A (V+ – V-)
In LtSpice Simulation, when the sum of feedback current through 1 Ohm Sense Resistor and Vin is greater than 6V by almost 0.6V, the output of OpAmp gets saturated at +Vcc and transistor current Ic doesn't change anymore.
2) In case Feedback is providing at inverting terminal from Emitter, I might assume V+ = V- and hence Ve = V-, which solves the problem. In this case, i am not sure if V+ = V- for an opamp, it doesn't come to be true from simulation either.
What would be the relation of output current with input voltage?
Thanks in anticipation.