Electronic – Understanding C20 value of lead battery for a low power circuit

battery-operatedlead-acid

I've developed a simple circuit using a Photon to send data to my database. It has to be a portable device and because of this I looked into lead batteries. My circuit runs on 5V and draws a maximum of 1A per day. I need it to run for about 2-3 weeks, continuously.

When looking at lead batteries, I see a lot about nominal capacity. For example: with this battery the nominal capacity at 1Ah at around 5.25V gives a C20 value of 20A.

Can this information give me any kind of indication about how long the battery will last if I draw only 1A per day? In an ideal situation, if I only draw 1A per 20 hours, this would mean I could run my circuit for 20 times 20 hours so a little over two weeks. But I doubt this is an ideal situation. What does this C20 tell me about a longer usage of the battery, if anything?

Based on the information of my circuit, what kind of battery can you recommend? I'm aware I need a buck converter as well, which power dissipation I have not taken into account for my calculations yet.

Thanks for any insights you can give me.

Best Answer

The C rating often used by RC LiPos is telling you about the ability to deliver the current mentioned. In your case 20A which will empty the Battery in less than 1/20 of an hour so after 3min you're done. The capacity you mentioned is 1Ah so given you draw 1A you'll get 1h of fun (at best). The math isn't really complicated. You mentioned that you expect the average current might be around 90mA so here you go 1Ah/0.09A=11h then your battery is empty. The C rating isn't at all important in your case.