Electronic – use a buck regulator for mains voltage if I put a resistor before it

buckpower supplyvoltage-regulator

I am reverse engineering a consumer product that I have, and the circuit seems to be mains voltage (85-250VAC) -> resistor (10ohm) -> bridge rectifier -> buck regulator -> linear regulator -> load.

The current is around 0.3A, output voltage is 3.3V. I would expect the resistor would be a very inefficient way of dropping the voltage. The application requires a very small power supply circuit and so a flyback with a transformer can not be used.

Is using a resistor + buck regulator as a power supply okay, or is there a much more efficient way of doing so?

Best Answer

$$\color{red}{\boxed{\text{A non-isolated mains AC power supply is a dangerous device - be warned}}}$$

However, if you want some recommendations I'd seek out Power Integrations and consider using this type of buck arrangement: -

enter image description here

Adding a 10 ohm resistor in series with the input is not unheard of as a way of cutting down the inrush current and, if you don't care too much about efficiency it can be many tens of ohms. The one above is a fusible resistor so maybe that is the part you actually saw.

Here's where you can find details on the LinkSwitch-TN2 device.