Electronic – What do they mean by “short-circuited” here


"Short-circuit inductance is the inductance when one of the primary winding or the secondary winding of the transformer is short-circuited and measured from the other winding."

I can't understand the part of the sentence in italic. What do they mean by "short-circuited" in this context? Even the image given in the Wiki page doesn't make much sense.

As far as I know, if an inductor is short-circuited it means there is connecting wire across it (i.e. the potential at both ends of inductor is same)

Source: https://en.wikipedia.org/wiki/Short-circuit_inductance

Best Answer

Just in case you do not read and speak our ordinary Mathjargonish well, I give more visual explanation:

enter image description here

The wire at the right is the short circuit. The short circuit inductance is what the inductance meter shows.

This test gives some numerical data of how far the transformer is from an ideal one. In ideal transformer the short circuit inductance is =0. In practice it's greater. To actually get some useful info, the wire at the right should be removed and also check, how much the inductance is without the short circuit. Ideally it should be infinite.

ADDENDUM due the comment:

The derivation of the formula for the short circuit inductance unfortunately needs the phasors or differential equations. Here the formula is derived in the simplest case (=no losses taken into the account):

enter image description here

The short circuit inductance has taken the place of the inductance in inductor's general equation between voltage and current.

Without the short circuit in secondary one can measure L1. Measuring the short circuit inductance is a way to get the k.