An open circuit, by definition, can have no current. A current source, by definition, has a non-zero current. The two are in series so the currents must be equal, but can't be. You have created an impossible circuit.
The dual of your impossible circuit would be an ideal voltage source into a short:
simulate this circuit – Schematic created using CircuitLab
A short, by definition, can have no voltage across it. A voltage source, by definition, does. The two are in parallel so the voltages must be equal, but can't be. This circuit is equally impossible.
You could say that the current in this circuit is infinite, and the the voltage in your circuit is infinite. What's the power in those circuits?
$$ P = I E = 1A \cdot \infty V = \infty W$$
$$ P = IE = \infty A \cdot 1V = \infty W $$
The power is infinite. What does that even mean? I have no idea: you will have to ask a mathematician.
If you were to consider that any two separated conductors are a capacitor, then maybe the circuit you had in mind was this:
simulate this circuit
Then yes, the voltage across C1 will increase, linearly, forever.
Best Answer
The current in any 2 terminal device is always the same, there's no way for a 2 terminal device to provide "extra" current. You can't have 0A in and 4A out.
What it does do is force the current to be the given value regardless of the impedance across it. (So therefore you can't put in an open circuit an ideal current source, the voltage would go to infinity.)
So a resistor by itself has no current through it. Hook it across an ideal current source and you get (for your example current source) 1A through it regardless of the value of the resistor.