Electronic – Where does inductor current go when the RL circuit switch opens

inductor

I'm struggling to wrap my head around a 'should-be-simple' problem involving an RL circuit. Referring to the image I've pasted below, what happens if we were to remove switch 1, and instead created a scenario where switch 2 simply opens? Where would the current go in the inductor?

I know that the current in an inductor can't instantaneously change, however, if switch 2 opens, it is now located on an abandoned branch thus can't allow current to flow…

How is the energy in the inductor is released?

enter image description here

Best Answer

The answer is found in Ohm's Law, with due notice taken of the amount of energy stored in the magnetic field. An open circuit is effectively an infinite resistance. For the same current to flow through such a resistance, the coil must develop an infinite voltage across itself.

In practice, this doesn't happen, of course. However, the coil does develop a high enough voltage to arc across the switch contacts as they open. This immediately discharges most of the energy in the magnetic field. The remaining energy dissipates rapidly as the magnetic field collapses.