In accumulation mode, the channel is not conducting, whereas in inversion mode it is conduting. But if in both cases I have free charge carriers in the channel, why isn't there conduction in both cases?
I know that the energy band diagram between the semiconductor and the oxide has a barrier for, say holes, and an accumulation well for electrons, but why would this have any influence on any barrier between the semiconductor and the source/drain?
(source)
Best Answer
Take NMOS as example, it has p-type body, and n-type drain and source.
If you apply a negative voltage on the gate, holes are drawn to the semiconductor-insulator interface. A conducting surface extends from the bulk all the way to the interface. But because both source and drain are n-type, in accumulation mode, it's like a npn transistor (source and drain are insulated by two reverse biased pn junctions), electrons in source can't go to drain. That is, there is no conduction channel formed.