Electronic – Why can the effective number of bits be a non-integer? What does this physically represent

adcdacsignalsignal processing

The effective number of bits (ENOB) describes the "real" resolution of an ADC.

I paid no attention to it when I was first taking the class but now when I think about it I cant really make sense of it that the result can be something like 6.8 bits. I can't really make sense of what 6.8 bits physically represent.

I would appreciate it if someone could expain why the ENOB isn't rounded down.

For instance why isn't ENOB = 6.8 = 6 bits? How would you interpret a rational ENOB in a real scnerio?

Best Answer

It is a result of calculating the number of bits after the imperfections such as noise and distortion are taken into account.

An ENOB of 6.8 basically tells you that for example an 8-bit ADC has real world performance that is better than an ideal 6-bit ADC but worse than an ideal 7-bit ADC.

You can also think of it as not having 2^6=64 or 2^7=128 discrete steps in the signal like on ideal 6 or 7 bit ADC, but 2^6.8 or about 111 discrete steps.