I do not understand why the current still flows through resistors R3 and R5 when R6 and R4's resistance is 0. To me, it would seem that the current would skip R3 and R5, however the answer key says otherwise. I have attached the problem and answer key. I realize that this is not the question being asked in the problem, however when I solved it I just took out the R3 and R5 so I got a different answer for the current flowing through the voltage source.
Circuit Analysis – Why Does Current Not Skip Resistors R3 and R5 When R6 and R4 Have No Resistance?
electricalengineering
Related Solutions
I confess to have understood only part of your questions. Anyway I will tray to share my (small?) experiences.
For the reverse protection my suggestion is to apply to the pins D and S of the device a simple resistor and a LED in the reverse polarity. It will light when the polarity is reverse.
- For the overcurrent or short circuit, if you don't need a very quick response, I want suggest you to use devices as Polyswitch. Applying in parallel to it the usual resistor and LED (in the direct way) you will see to light it when the current it's been behind the 'Trip current' for enough time to turn the Polyswitch in the open (not absolute) state.
I hope that this my answer will be useful to 'tune' me into your problem.
The ground symbol is misleading. The lamps are connected to each other. This completes the circuit from one side of the transformer to the other. This illuminates both lamps in series.
If only one lamp is connected then nothing would happen.
simulate this circuit – Schematic created using CircuitLab
This is what the effective circuit looks like.
As far as the voltage after the transformer, you have to pick a reference yourself. But now you only have two choices. One wire is the reference and the other is hot. The hot wire goes +230 then -230 then +230 when compared to the reference.
Best Answer
With R4 and R6 being zero, this means they are essentially a short circuit. You should imagine the initial circuit to look like this:
simulate this circuit – Schematic created using CircuitLab
This now becomes much easier to visualise.
I believe what happened here is you mistook the meaning. Where you removed them from the circuit, what you should have done is just replaced them with a wire as shown above. When you do this, you can see that R3 and R5 are connected straight across the supply voltage, so there must be current flowing through them. From here, you can re-draw and simplify the circuit to solve.