I want to make an oscillator for my step up transformer but I can't use an ordinary one because I can't buy anything right now. I have a few components (resistors and exactly two tranzistors). So I came up with this oscillator:
simulate this circuit – Schematic created using CircuitLab
At the beginng the Q2 starts to conduct because it has voltage on his gate so it charges the capacitor. After this step the Q1 is quickly turn on which turns off Q2 but it remainslike that until C1 discharges on R1…And then it starts over again create a square wave (almost).
But when I tried to build it, it failed… Why? What is wrong with this circuit and can you explain why ? And don't tell me that there are other oscillators (I tried arduino but I fried it…) Thank you in advance..
Best Answer
Q3 will work upside down; the hFE will be low but it will still work as a transistor (it will actually saturate at a lower voltage but that is besides the point).
Why doesn't this work? Or better still why do relaxation oscillators work - the simple answer is hysteresis. Your circuit has no hysteresis therefore it operates in a linear fashion and finds a perfectly likable equilibrium with about 0.7 volts across R2.
What would have been preferred is for Q3 to act like a trigger - once activated it stays activated until the voltage across C1/R2 has dropped (maybe) to 50%. Then the whole process will start again with C1 rapidly charging then triggering Q2 which then discharges C1/R2 thus an oscillator is created. Remember that Q3 can work upside down and the base-collector region is the new base-emitter region.
Sorry, it won't happen like that in a linear circuit - it just finds a nice equilibrium and sits there. Relation oscillators need hysteresis! Here's the archetypal op-amp relation oscillator: -
R3 and R2 provide positive feedback and this creates hysteresis. Here's a useful oscillator to try: -
It's called an astable multivibrator but if you want some other options hit this link.