Inrush current is greatest when operating no-load on secondary
Is it a problem of having no load?
Yes, it might be significant.
Most likely the problem is "inrush current" and this is due to saturation of the transformer core. At this point some folk may be shaking their heads and not believing this and they may point out that "surely the current will be greater when the transformer secondary is fully loaded and surely this will produce more saturation in the core?"
The magnetization of the transformer core is due to the inductance \$X_M\$shown below (with a blue box around it: -
![enter image description here](https://i.stack.imgur.com/ikMt5.jpg)
This is the equivalent circuit of a transformer and shows other stuff like iron loss and copper losses. When the transformer secondary is open circuit, the copper losses are extremely small and can be ignored; the upshot is that \$X_M\$ receives the full supply voltage because there is minimal volts dropped across the copper loss components and leakage inductance.
This means that the magnetization of the transformer is at its highest because when secondary current flows (due to load), the volts on \$X_M\$ reduce slightly due to \$R_P\$ and \$X_P\$.
But why should the core saturate? Here's what the magnetic field looks like when power is applied when \$V_P\$ is at the top of its voltage cycle: -
![enter image description here](https://i.stack.imgur.com/eFMPM.jpg)
The voltage waveform is in black and the magnetic flux (or current) is in red. Forgive my drawing ability. Two scenarios and one produces normal peaks of current (as if the supply had been connected forever) and the other scenario causes the current to hit a big high-spot then settles down.
There's nothing mystical about this - this is what would happen in an inductor if you simulated it (look at the current).
If the magnetizing current peak is bigger, then so is the driving force of the magnetic field. If you looked at what the flux density is like when the ampere-turns are bigger you are likely to see the flux reach saturation and, when this happens you also draw a lot more current which in turn makes the problem bigger. This settles down after a few cycles of the power waveform of course.
What you will probably find is that sometimes the current limit trips and sometimes it doesn't - it's all down to where on the voltage cycle you applied power to the transformer.
Even fast fuses don't respond immediately after the rated current is reached. Most fuses require a significant over current to fire almost instantly. This is an obvious requirement since its all about heat, and minor heating (a raise ambient temperature) shouldn't affect the fuse too much (or at least not cause it to "blow").
Judging from the data-sheet, your 100mA fuse should blow after about 80 seconds @215mA @25°C.
![enter image description here](https://i.stack.imgur.com/xE2Lg.png)
How long did you wait?
Best Answer
Use a different fuse, you most likely used a fast blowing fuse which trips as soon as an overcurrent occurs.
Instead use a slow blowing fuse which will trip slower and allows the inrush current that charges the capacitors to pass through without tripping.