Why is the amount of charge on every capacitor in series equal, regardless that capacitance values of capacitors are not the same? What really happens here so they are the same?
simulate this circuit – Schematic created using CircuitLab
capacitancecapacitorcircuit analysis
Why is the amount of charge on every capacitor in series equal, regardless that capacitance values of capacitors are not the same? What really happens here so they are the same?
simulate this circuit – Schematic created using CircuitLab
Best Answer
Charge cannot be created or destroyed. Since you only have one possible current path through all the capacitors (and current is just flowing charge) the charge on all 3 capacitors has to be the same. The capacitance of the capacitor indicates how much voltage a particular amount of charge corresponds to Q/C = V. Put more charge into a cap, get a bigger voltage difference. Put the same charge in a smaller cap, get a bigger voltage difference. So what happens in your circuit is that the charge is distributed evenly, but the applied voltage is distributed according to the capacitor sizes, with the smallest cap ending up with the largest fraction of the applied voltage.