I was reading about Frequency modulated Continuous wave radar but still struggling to understand it.
I have a few questions in the slide above. The blue line in the graph represents the transmitted signal and red the received signal. If the receiver output is pure sinusoid as is shown in lower graph why is its frequency vs time graph linear (red line). Shouldn't it contain a single frequency?
I also do not understand why the FFT of the received output gives us the range of the obstacle. And again, how its FFT gives us the velocity.
Could anyone please explain this to me.
The snippet above is from slides from TU-Delft, which can be found here:
http://www.slideshare.net/tobiasotto/principle-of-fmcw-radars
Best Answer
The receiver's output is not the red line. Instead, it is the beat frequency between red line and blue line. f(beat) = f(blue)-f(red) = fb;
The receiver calculates fb, which is the center frequency shown in FFT diagram. Knowing fb, you can calculate R from the formula $$R=c*Ts*Fb/2Bsweep $$
Check out slide page 9. The diagram you posted indicates the condition when the detected object does not move. What may happen if the object moves? If the detected moves relative to receiver, doplar effect will start to work. Therefore you have a different frequency, which is doplar frequency.
Check the bottom diagram of slide page 9, it shows the condition when the object move: combination of doplar effect and previous frequency shift.