Suppose if I have a Vdd of 1.4V and I want to generate 1.2V and 1V constant voltages even when there are slight changes in the load values, is there any possible way of achieving this?
Well I tried doing this by using current mirrors and resistance ladders, but I couldn't achieve constant voltages from it because the load was changing. Can any modification be made to these methods or is there any solution for this?
Edit 1 :
This question has been asked in the perspective of IC Designing where I'm trying to lower the power dissipation my designed circuit by giving lower supply voltages to some of the components. Now the only way I can do this is if I can generate these voltages from Vdd considering I want only only one power pin in the IC.
Edit 2(3) :
The value of the current taken by the vdd is in the range of mA and the one needed for the 1V is around 80uA
Best Answer
Unless you somehow manage to integrate an inductor inside your chip so that a buck regulator can be realized, using any form of linear regulator to step down a voltage to a lower level is NOT going to "consume" less power (watts) for the same current drawn.
Linear regulators work by just burning-off the excess voltage as heat so there's no net power saving. Of course, if lowering the voltage also lowers the current then this does give a saving but, at the 100 uA level I think you'll be wasting your time and I would recommend trying to figure ways to make your basic circuits take less current.
That is my advice.