How does the function inside the rectangular function work

signalsystem

I'm looking at a Signals and Systems problem, and the question asks to show the inverse fourier transform of \$f(w)=\operatorname{rect}(\frac{w-10}{2\pi})\$ is:

$$\mathcal{F}_{t}^{-1}[f(w)]=\operatorname{sinc}(\pi t)e^{10jt}$$

I can see that \$\operatorname{rect}(x)\$ becomes \$1\$ over the interval \$-1/2\$ to \$1/2\$, but how is it affected by a more complex function? In the solutions we were given the bounds become \$10-\pi\$ to \$10+\pi\$. How did they get to these bounds?

Best Answer

\$\operatorname{rect}(\cdot)\$ is a function that has value \$1\$ if whatever appears inside those parentheses (it's called the argument of the rect function and I used \$\cdot\$ instead of some algebraic variable as a place holder) has value between \$-\frac 12\$ and \$+\frac 12\$. Otherwise, when the argument is strictly smaller than \$-\frac 12\$ (or strictly larger than \$+\frac 12\$), \$\operatorname{rect}(\cdot)\$ has value \$0\$. In your instance, you need to ask

For what values of \$\omega\$ does \$\displaystyle \frac{\omega - 10}{2\pi}\$ equal a number between \$-\frac 12\$ and \$\frac 12\$?

and a little thought will show, I hope, that \$\omega\$ must be in the interval from \$10-\pi\$ to \$10 + \pi\$. If you have trouble deriving this, try and find the value of \$\omega\$ that makes \$\displaystyle \frac{\omega - 10}{2\pi}\$ equal exactly \$-\frac 12\$ and then, lather, rinse and repeat for exactly \$\frac 12\$.