Operational Amplifier – How Does This Offset and Gain Amplifier Work?

First, the DUT is in the positive feedback because this way you have an inverting and a non-inverting gain in the loop, so that multiplying them you obtain an overall negative loop gain.

Second, the gain is 1000 because Vin of DUT is Vos*50/(50K+50), so if you consider that V+ of the DUT should be 0, there is only the offset applied, so the feedback forces the output to be 1k times the offset voltage.

I think that you can look at the output this way: suppose that the situation is the one described, and you have a 500uV DUT offset and so 500mV output voltage.

Now, if you try to perturb the Servo Input, the feedback forces the output of the DUT to be almost the same of Servo Input, restoring the same Output voltage.

Note: Voff is the conventional name for input offset voltage, while Vos is the output voltage with Voff applied at the input pins.

As shown the circuit does not work [tm].

Overall, without intending to be rude, I'd say the circuit was "designed" by someone with a poor understanding of the task and also drawn incorrectly.

• BA10358 datasheet here - immensely detailed information but seems normal enough. 0.2 V/uS slew rate and 0.5 MHz "bandwidth".

As shown, U1A inverting input is at 11 to 14V and the non inverting input is at 5V plus whatever effect the hysteresis / +ve feedback via R2 - probably about +/1 1 Volt - see below. Consequently, U4A can never switch.

The most likely explanation is that the variable resistor is not connected as shown but has one end of the resistive track connected to input (as shown), the wiper connected to U4A inverting input (as shown) BUT the other end of the resistor track grounded. This is "quite a leap" but nothing else makes sense. With the change the input to the opamp can be varied from Vtest down to ground.

If opamp supply and max Vout was say +10V then the Schmitt trigger formed by U4A would switch at about 6V when the input was rising and about 4V when the inout was falling.

As I think you know - IF the circuit was arranged as above, U4A is a comparator configured as a Schmitt trigger due to positive feedback via R12. As R12 is 100k would have 10 times less effect in the trigger level than R1 does as R1/R12 = 19k/100k BUT opamp Vout max+ is say 10V so has 10V/5V = twice as much effect - so 1/10 x 2/1 = 1/5 as much effect overall. So as Vref = 5V the feedback moved the switching point by ABOUT 1V to 6V and 4V on rising and falling inputs respectively.

The circuitry around U4B (also) appears to have been designed by somebody who did not understand what they were doing. Apart from the effect if input leakage currents of U4b, the resistors R3 and R4 have no effect. U4 pins 3 & 5 are effecively at the same potential. U4 pins 1 & 6 are effectively at the same potential.

U4B seems to serve little function except to invert the polarity of U4A and PERHAPS speed up overall switching speed at the output.
When input is low U4B "sees" Vrfe +1V on +in and - Vmax_-ve_swing on -in. U4B output is low with Vin low.
When the Schmitt starts to switch with rising Vin both inputs of U4B fall but the -in from u4A falls further and toggles U4B. If anything this MAY slow down the switching action as both inputs track in the same direction, but one swings further, so there is negative reinforcement around the switching point.
Strange.

This opamp is cheap. Under $US0.20 in manufacturinmg volumes. BUT here it is being used as a comparator and it is not well suited to that task. Slew rate is a miserable 0.2 V/uS and maximum frequency (whatever that spec means here) is 0.5 MHz.